6(10-c)=2

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Solution for 6(10-c)=2 equation: 



6(10-c)=2

We move all terms to the left:

6(10-c)-(2)=0

We add all the numbers together, and all the variables

6(-1c+10)-2=0

We multiply parentheses

-6c+60-2=0

We add all the numbers together, and all the variables

-6c+58=0

We move all terms containing c to the left, all other terms to the right

-6c=-58

c=-58/-6

c=9+2/3

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