6(11-y)+9=-9(y-4)-3

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Solution for 6(11-y)+9=-9(y-4)-3 equation: 



6(11-y)+9=-9(y-4)-3

We move all terms to the left:

6(11-y)+9-(-9(y-4)-3)=0

We add all the numbers together, and all the variables

6(-1y+11)-(-9(y-4)-3)+9=0

We multiply parentheses

-6y-(-9(y-4)-3)+66+9=0



We calculate terms in parentheses: -(-9(y-4)-3), so:

-9(y-4)-3

We multiply parentheses

-9y+36-3

We add all the numbers together, and all the variables

-9y+33

Back to the equation:

-(-9y+33)



We add all the numbers together, and all the variables

-6y-(-9y+33)+75=0

We get rid of parentheses

-6y+9y-33+75=0

We add all the numbers together, and all the variables

3y+42=0

We move all terms containing y to the left, all other terms to the right

3y=-42

y=-42/3

y=-14

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