6(12z-12)=-4(-3-11z)

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Solution for 6(12z-12)=-4(-3-11z) equation:



6(12z-12)=-4(-3-11z)
We move all terms to the left:
6(12z-12)-(-4(-3-11z))=0
We add all the numbers together, and all the variables
6(12z-12)-(-4(-11z-3))=0
We multiply parentheses
72z-(-4(-11z-3))-72=0
We calculate terms in parentheses: -(-4(-11z-3)), so:
-4(-11z-3)
We multiply parentheses
44z+12
Back to the equation:
-(44z+12)
We get rid of parentheses
72z-44z-12-72=0
We add all the numbers together, and all the variables
28z-84=0
We move all terms containing z to the left, all other terms to the right
28z=84
z=84/28
z=3

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