6(13+5z/2)+3z=10

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Solution for 6(13+5z/2)+3z=10 equation:



6(13+5z/2)+3z=10
We move all terms to the left:
6(13+5z/2)+3z-(10)=0
We add all the numbers together, and all the variables
6(5z/2+13)+3z-10=0
We add all the numbers together, and all the variables
3z+6(5z/2+13)-10=0
We multiply parentheses
3z+30z+78-10=0
We add all the numbers together, and all the variables
33z+68=0
We move all terms containing z to the left, all other terms to the right
33z=-68
z=-68/33
z=-2+2/33

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