6(13-2i)=3(3i-2)

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Solution for 6(13-2i)=3(3i-2) equation: 



6(13-2i)=3(3i-2)

We move all terms to the left:

6(13-2i)-(3(3i-2))=0

We add all the numbers together, and all the variables

6(-2i+13)-(3(3i-2))=0

We multiply parentheses

-12i-(3(3i-2))+78=0



We calculate terms in parentheses: -(3(3i-2)), so:

3(3i-2)

We multiply parentheses

9i-6

Back to the equation:

-(9i-6)



We get rid of parentheses

-12i-9i+6+78=0

We add all the numbers together, and all the variables

-21i+84=0

We move all terms containing i to the left, all other terms to the right

-21i=-84

i=-84/-21

i=+4

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