6(16-x)-9(15-2x)=18(x-3)+3

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Solution for 6(16-x)-9(15-2x)=18(x-3)+3 equation: 



6(16-x)-9(15-2x)=18(x-3)+3

We move all terms to the left:

6(16-x)-9(15-2x)-(18(x-3)+3)=0

We add all the numbers together, and all the variables

6(-1x+16)-9(-2x+15)-(18(x-3)+3)=0

We multiply parentheses

-6x+18x-(18(x-3)+3)+96-135=0



We calculate terms in parentheses: -(18(x-3)+3), so:

18(x-3)+3

We multiply parentheses

18x-54+3

We add all the numbers together, and all the variables

18x-51

Back to the equation:

-(18x-51)



We add all the numbers together, and all the variables

12x-(18x-51)-39=0

We get rid of parentheses

12x-18x+51-39=0

We add all the numbers together, and all the variables

-6x+12=0

We move all terms containing x to the left, all other terms to the right

-6x=-12

x=-12/-6

x=+2

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