6(1f+5)=2f-8

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Solution for 6(1f+5)=2f-8 equation: 



6(1f+5)=2f-8

We move all terms to the left:

6(1f+5)-(2f-8)=0

We add all the numbers together, and all the variables

6(f+5)-(2f-8)=0

We multiply parentheses

6f-(2f-8)+30=0

We get rid of parentheses

6f-2f+8+30=0

We add all the numbers together, and all the variables

4f+38=0

We move all terms containing f to the left, all other terms to the right

4f=-38

f=-38/4

f=-9+1/2

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