6(1x+2)+4(1x+2)=36

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Solution for 6(1x+2)+4(1x+2)=36 equation: 



6(1x+2)+4(1x+2)=36

We move all terms to the left:

6(1x+2)+4(1x+2)-(36)=0

We add all the numbers together, and all the variables

6(x+2)+4(x+2)-36=0

We multiply parentheses

6x+4x+12+8-36=0

We add all the numbers together, and all the variables

10x-16=0

We move all terms containing x to the left, all other terms to the right

10x=16

x=16/10

x=1+3/5

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