6(2+3)-5(3z+2)=2(2z-9)

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Solution for 6(2+3)-5(3z+2)=2(2z-9) equation:


Simplifying
6(2 + 3) + -5(3z + 2) = 2(2z + -9)

Combine like terms: 2 + 3 = 5
6(5) + -5(3z + 2) = 2(2z + -9)

Multiply 6 * 5
30 + -5(3z + 2) = 2(2z + -9)

Reorder the terms:
30 + -5(2 + 3z) = 2(2z + -9)
30 + (2 * -5 + 3z * -5) = 2(2z + -9)
30 + (-10 + -15z) = 2(2z + -9)

Combine like terms: 30 + -10 = 20
20 + -15z = 2(2z + -9)

Reorder the terms:
20 + -15z = 2(-9 + 2z)
20 + -15z = (-9 * 2 + 2z * 2)
20 + -15z = (-18 + 4z)

Solving
20 + -15z = -18 + 4z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-4z' to each side of the equation.
20 + -15z + -4z = -18 + 4z + -4z

Combine like terms: -15z + -4z = -19z
20 + -19z = -18 + 4z + -4z

Combine like terms: 4z + -4z = 0
20 + -19z = -18 + 0
20 + -19z = -18

Add '-20' to each side of the equation.
20 + -20 + -19z = -18 + -20

Combine like terms: 20 + -20 = 0
0 + -19z = -18 + -20
-19z = -18 + -20

Combine like terms: -18 + -20 = -38
-19z = -38

Divide each side by '-19'.
z = 2

Simplifying
z = 2

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