6(2+3c)=56

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Solution for 6(2+3c)=56 equation: 



6(2+3c)=56

We move all terms to the left:

6(2+3c)-(56)=0

We add all the numbers together, and all the variables

6(3c+2)-56=0

We multiply parentheses

18c+12-56=0

We add all the numbers together, and all the variables

18c-44=0

We move all terms containing c to the left, all other terms to the right

18c=44

c=44/18

c=2+4/9

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