6(2+3m)=4(6+3m)

Solution for 6(2+3m)=4(6+3m) equation:

6(2+3m)=4(6+3m)

We move all terms to the left:

6(2+3m)-(4(6+3m))=0

We add all the numbers together, and all the variables

6(3m+2)-(4(3m+6))=0

We multiply parentheses

18m-(4(3m+6))+12=0


We calculate terms in parentheses: -(4(3m+6)), so:

4(3m+6)

We multiply parentheses

12m+24

Back to the equation:

-(12m+24)


We get rid of parentheses

18m-12m-24+12=0

We add all the numbers together, and all the variables

6m-12=0

We move all terms containing m to the left, all other terms to the right

6m=12

m=12/6

m=2