6(2+3z)=12+18z

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Solution for 6(2+3z)=12+18z equation:


Simplifying
6(2 + 3z) = 12 + 18z
(2 * 6 + 3z * 6) = 12 + 18z
(12 + 18z) = 12 + 18z

Add '-12' to each side of the equation.
12 + -12 + 18z = 12 + -12 + 18z

Combine like terms: 12 + -12 = 0
0 + 18z = 12 + -12 + 18z
18z = 12 + -12 + 18z

Combine like terms: 12 + -12 = 0
18z = 0 + 18z
18z = 18z

Add '-18z' to each side of the equation.
18z + -18z = 18z + -18z

Combine like terms: 18z + -18z = 0
0 = 18z + -18z

Combine like terms: 18z + -18z = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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