6(2+c)=5(c+-2)

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Solution for 6(2+c)=5(c+-2) equation:


Simplifying
6(2 + c) = 5(c + -2)
(2 * 6 + c * 6) = 5(c + -2)
(12 + 6c) = 5(c + -2)

Reorder the terms:
12 + 6c = 5(-2 + c)
12 + 6c = (-2 * 5 + c * 5)
12 + 6c = (-10 + 5c)

Solving
12 + 6c = -10 + 5c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-5c' to each side of the equation.
12 + 6c + -5c = -10 + 5c + -5c

Combine like terms: 6c + -5c = 1c
12 + 1c = -10 + 5c + -5c

Combine like terms: 5c + -5c = 0
12 + 1c = -10 + 0
12 + 1c = -10

Add '-12' to each side of the equation.
12 + -12 + 1c = -10 + -12

Combine like terms: 12 + -12 = 0
0 + 1c = -10 + -12
1c = -10 + -12

Combine like terms: -10 + -12 = -22
1c = -22

Divide each side by '1'.
c = -22

Simplifying
c = -22

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