6(2+c)=5(c-1)

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Solution for 6(2+c)=5(c-1) equation:


Simplifying
6(2 + c) = 5(c + -1)
(2 * 6 + c * 6) = 5(c + -1)
(12 + 6c) = 5(c + -1)

Reorder the terms:
12 + 6c = 5(-1 + c)
12 + 6c = (-1 * 5 + c * 5)
12 + 6c = (-5 + 5c)

Solving
12 + 6c = -5 + 5c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-5c' to each side of the equation.
12 + 6c + -5c = -5 + 5c + -5c

Combine like terms: 6c + -5c = 1c
12 + 1c = -5 + 5c + -5c

Combine like terms: 5c + -5c = 0
12 + 1c = -5 + 0
12 + 1c = -5

Add '-12' to each side of the equation.
12 + -12 + 1c = -5 + -12

Combine like terms: 12 + -12 = 0
0 + 1c = -5 + -12
1c = -5 + -12

Combine like terms: -5 + -12 = -17
1c = -17

Divide each side by '1'.
c = -17

Simplifying
c = -17

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