6(2+r)=1/3(4r+6)

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Solution for 6(2+r)=1/3(4r+6) equation: 



6(2+r)=1/3(4r+6)

We move all terms to the left:

6(2+r)-(1/3(4r+6))=0



Domain of the equation: 3(4r+6))!=0

r∈R



We add all the numbers together, and all the variables

6(r+2)-(1/3(4r+6))=0

We multiply parentheses

6r-(1/3(4r+6))+12=0

We multiply all the terms by the denominator


6r*3(4r+6))-(1+12*3(4r+6))=0

Wy multiply elements

18r^2(4+36r(4=0

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