6(2+s)=(3+s)

Solution for 6(2+s)=(3+s) equation:

6(2+s)=(3+s)

We move all terms to the left:

6(2+s)-((3+s))=0

We add all the numbers together, and all the variables

6(s+2)-((s+3))=0

We multiply parentheses

6s-((s+3))+12=0


We calculate terms in parentheses: -((s+3)), so:

(s+3)

We get rid of parentheses

s+3

Back to the equation:

-(s+3)


We get rid of parentheses

6s-s-3+12=0

We add all the numbers together, and all the variables

5s+9=0

We move all terms containing s to the left, all other terms to the right

5s=-9

s=-9/5

s=-1+4/5