6(2+s)=3-s

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Solution for 6(2+s)=3-s equation: 



6(2+s)=3-s

We move all terms to the left:

6(2+s)-(3-s)=0

We add all the numbers together, and all the variables

6(s+2)-(-1s+3)=0

We multiply parentheses

6s-(-1s+3)+12=0

We get rid of parentheses

6s+1s-3+12=0

We add all the numbers together, and all the variables

7s+9=0

We move all terms containing s to the left, all other terms to the right

7s=-9

s=-9/7

s=-1+2/7

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