6(2+v)-2v=v+16

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Solution for 6(2+v)-2v=v+16 equation: 



6(2+v)-2v=v+16

We move all terms to the left:

6(2+v)-2v-(v+16)=0

We add all the numbers together, and all the variables

6(v+2)-2v-(v+16)=0

We add all the numbers together, and all the variables

-2v+6(v+2)-(v+16)=0

We multiply parentheses

-2v+6v-(v+16)+12=0

We get rid of parentheses

-2v+6v-v-16+12=0

We add all the numbers together, and all the variables

3v-4=0

We move all terms containing v to the left, all other terms to the right

3v=4

v=4/3

v=1+1/3

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