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6(2+y)=(3+y)
We move all terms to the left:
6(2+y)-((3+y))=0
We add all the numbers together, and all the variables
6(y+2)-((y+3))=0
We multiply parentheses
6y-((y+3))+12=0
We calculate terms in parentheses: -((y+3)), so:We get rid of parentheses
(y+3)
We get rid of parentheses
y+3
Back to the equation:
-(y+3)
6y-y-3+12=0
We add all the numbers together, and all the variables
5y+9=0
We move all terms containing y to the left, all other terms to the right
5y=-9
y=-9/5
y=-1+4/5
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