6(2+y)=3(3-y)*

Solution for 6(2+y)=3(3-y)* equation:

6(2+y)=3(3-y)*

We move all terms to the left:

6(2+y)-(3(3-y)*)=0

We add all the numbers together, and all the variables

6(y+2)-(3(-1y+3)*)=0

We multiply parentheses

6y-(3(-1y+3)*)+12=0


We calculate terms in parentheses: -(3(-1y+3)*), so:

3(-1y+3)*

We multiply parentheses

-3y+9

Back to the equation:

-(-3y+9)


We get rid of parentheses

6y+3y-9+12=0

We add all the numbers together, and all the variables

9y+3=0

We move all terms containing y to the left, all other terms to the right

9y=-3

y=-3/9

y=-1/3