6(2+y)=3(3-y)+12

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Solution for 6(2+y)=3(3-y)+12 equation: 



6(2+y)=3(3-y)+12

We move all terms to the left:

6(2+y)-(3(3-y)+12)=0

We add all the numbers together, and all the variables

6(y+2)-(3(-1y+3)+12)=0

We multiply parentheses

6y-(3(-1y+3)+12)+12=0



We calculate terms in parentheses: -(3(-1y+3)+12), so:

3(-1y+3)+12

We multiply parentheses

-3y+9+12

We add all the numbers together, and all the variables

-3y+21

Back to the equation:

-(-3y+21)



We get rid of parentheses

6y+3y-21+12=0

We add all the numbers together, and all the variables

9y-9=0

We move all terms containing y to the left, all other terms to the right

9y=9

y=9/9

y=1

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