6(2+y)=3(3-y)+2

Solution for 6(2+y)=3(3-y)+2 equation:

6(2+y)=3(3-y)+2

We move all terms to the left:

6(2+y)-(3(3-y)+2)=0

We add all the numbers together, and all the variables

6(y+2)-(3(-1y+3)+2)=0

We multiply parentheses

6y-(3(-1y+3)+2)+12=0


We calculate terms in parentheses: -(3(-1y+3)+2), so:

3(-1y+3)+2

We multiply parentheses

-3y+9+2

We add all the numbers together, and all the variables

-3y+11

Back to the equation:

-(-3y+11)


We get rid of parentheses

6y+3y-11+12=0

We add all the numbers together, and all the variables

9y+1=0

We move all terms containing y to the left, all other terms to the right

9y=-1

y=-1/9

y=-1/9