6(2+y)=3(3-y)=

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Solution for 6(2+y)=3(3-y)= equation: 



6(2+y)=3(3-y)=

We move all terms to the left:

6(2+y)-(3(3-y))=0

We add all the numbers together, and all the variables

6(y+2)-(3(-1y+3))=0

We multiply parentheses

6y-(3(-1y+3))+12=0



We calculate terms in parentheses: -(3(-1y+3)), so:

3(-1y+3)

We multiply parentheses

-3y+9

Back to the equation:

-(-3y+9)



We get rid of parentheses

6y+3y-9+12=0

We add all the numbers together, and all the variables

9y+3=0

We move all terms containing y to the left, all other terms to the right

9y=-3

y=-3/9

y=-1/3

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