6(2-2x)=-8x+40

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Solution for 6(2-2x)=-8x+40 equation: 



6(2-2x)=-8x+40

We move all terms to the left:

6(2-2x)-(-8x+40)=0

We add all the numbers together, and all the variables

6(-2x+2)-(-8x+40)=0

We multiply parentheses

-12x-(-8x+40)+12=0

We get rid of parentheses

-12x+8x-40+12=0

We add all the numbers together, and all the variables

-4x-28=0

We move all terms containing x to the left, all other terms to the right

-4x=28

x=28/-4

x=-7

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