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6(2-3x)=5x-2-(x-4)
We move all terms to the left:
6(2-3x)-(5x-2-(x-4))=0
We add all the numbers together, and all the variables
6(-3x+2)-(5x-2-(x-4))=0
We multiply parentheses
-18x-(5x-2-(x-4))+12=0
We calculate terms in parentheses: -(5x-2-(x-4)), so:We get rid of parentheses
5x-2-(x-4)
determiningTheFunctionDomain 5x-(x-4)-2
We get rid of parentheses
5x-x+4-2
We add all the numbers together, and all the variables
4x+2
Back to the equation:
-(4x+2)
-18x-4x-2+12=0
We add all the numbers together, and all the variables
-22x+10=0
We move all terms containing x to the left, all other terms to the right
-22x=-10
x=-10/-22
x=5/11
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