6(2-4)+1=3s+7

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Solution for 6(2-4)+1=3s+7 equation:



6(2-4)+1=3s+7
We move all terms to the left:
6(2-4)+1-(3s+7)=0
We add all the numbers together, and all the variables
-(3s+7)+1+6(-2)=0
We add all the numbers together, and all the variables
-(3s+7)-11=0
We get rid of parentheses
-3s-7-11=0
We add all the numbers together, and all the variables
-3s-18=0
We move all terms containing s to the left, all other terms to the right
-3s=18
s=18/-3
s=-6

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