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6(2-5z)-3z=10z-160
We move all terms to the left:
6(2-5z)-3z-(10z-160)=0
We add all the numbers together, and all the variables
6(-5z+2)-3z-(10z-160)=0
We add all the numbers together, and all the variables
-3z+6(-5z+2)-(10z-160)=0
We multiply parentheses
-3z-30z-(10z-160)+12=0
We get rid of parentheses
-3z-30z-10z+160+12=0
We add all the numbers together, and all the variables
-43z+172=0
We move all terms containing z to the left, all other terms to the right
-43z=-172
z=-172/-43
z=+4
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