6(2-c)=8-2c

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Solution for 6(2-c)=8-2c equation: 



6(2-c)=8-2c

We move all terms to the left:

6(2-c)-(8-2c)=0

We add all the numbers together, and all the variables

6(-1c+2)-(-2c+8)=0

We multiply parentheses

-6c-(-2c+8)+12=0

We get rid of parentheses

-6c+2c-8+12=0

We add all the numbers together, and all the variables

-4c+4=0

We move all terms containing c to the left, all other terms to the right

-4c=-4

c=-4/-4

c=1

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