6(2-d)=(d-4)

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Solution for 6(2-d)=(d-4) equation: 



6(2-d)=(d-4)

We move all terms to the left:

6(2-d)-((d-4))=0

We add all the numbers together, and all the variables

6(-1d+2)-((d-4))=0

We multiply parentheses

-6d-((d-4))+12=0



We calculate terms in parentheses: -((d-4)), so:

(d-4)

We get rid of parentheses

d-4

Back to the equation:

-(d-4)



We get rid of parentheses

-6d-d+4+12=0

We add all the numbers together, and all the variables

-7d+16=0

We move all terms containing d to the left, all other terms to the right

-7d=-16

d=-16/-7

d=2+2/7

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