6(2-d)=9(d-4

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Solution for 6(2-d)=9(d-4 equation: 



6(2-d)=9(d-4

We move all terms to the left:

6(2-d)-(9(d-4)=0

We add all the numbers together, and all the variables

6(-1d+2)-(9(d-4)=0

We multiply parentheses

-6d-(9(d-4)+12=0

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