6(2-n)=4(n+8)

Solution for 6(2-n)=4(n+8) equation:

6(2-n)=4(n+8)

We move all terms to the left:

6(2-n)-(4(n+8))=0

We add all the numbers together, and all the variables

6(-1n+2)-(4(n+8))=0

We multiply parentheses

-6n-(4(n+8))+12=0


We calculate terms in parentheses: -(4(n+8)), so:

4(n+8)

We multiply parentheses

4n+32

Back to the equation:

-(4n+32)


We get rid of parentheses

-6n-4n-32+12=0

We add all the numbers together, and all the variables

-10n-20=0

We move all terms containing n to the left, all other terms to the right

-10n=20

n=20/-10

n=-2