6(2-p)=4(p+3)

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Solution for 6(2-p)=4(p+3) equation: 



6(2-p)=4(p+3)

We move all terms to the left:

6(2-p)-(4(p+3))=0

We add all the numbers together, and all the variables

6(-1p+2)-(4(p+3))=0

We multiply parentheses

-6p-(4(p+3))+12=0



We calculate terms in parentheses: -(4(p+3)), so:

4(p+3)

We multiply parentheses

4p+12

Back to the equation:

-(4p+12)



We get rid of parentheses

-6p-4p-12+12=0

We add all the numbers together, and all the variables

-10p=0

p=0/-10

p=0

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