6(2-v)-v=2(v+1)

Solution for 6(2-v)-v=2(v+1) equation:

6(2-v)-v=2(v+1)

We move all terms to the left:

6(2-v)-v-(2(v+1))=0

We add all the numbers together, and all the variables

6(-1v+2)-v-(2(v+1))=0

We add all the numbers together, and all the variables

-1v+6(-1v+2)-(2(v+1))=0

We multiply parentheses

-1v-6v-(2(v+1))+12=0


We calculate terms in parentheses: -(2(v+1)), so:

2(v+1)

We multiply parentheses

2v+2

Back to the equation:

-(2v+2)


We add all the numbers together, and all the variables

-7v-(2v+2)+12=0

We get rid of parentheses

-7v-2v-2+12=0

We add all the numbers together, and all the variables

-9v+10=0

We move all terms containing v to the left, all other terms to the right

-9v=-10

v=-10/-9

v=1+1/9