6(2-x)+8x=10

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Solution for 6(2-x)+8x=10 equation: 



6(2-x)+8x=10

We move all terms to the left:

6(2-x)+8x-(10)=0

We add all the numbers together, and all the variables

6(-1x+2)+8x-10=0

We add all the numbers together, and all the variables

8x+6(-1x+2)-10=0

We multiply parentheses

8x-6x+12-10=0

We add all the numbers together, and all the variables

2x+2=0

We move all terms containing x to the left, all other terms to the right

2x=-2

x=-2/2

x=-1

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