6(2-x)-(5x+2)=8+3(x-4)

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Solution for 6(2-x)-(5x+2)=8+3(x-4) equation: 



6(2-x)-(5x+2)=8+3(x-4)

We move all terms to the left:

6(2-x)-(5x+2)-(8+3(x-4))=0

We add all the numbers together, and all the variables

6(-1x+2)-(5x+2)-(8+3(x-4))=0

We multiply parentheses

-6x-(5x+2)-(8+3(x-4))+12=0

We get rid of parentheses

-6x-5x-(8+3(x-4))-2+12=0



We calculate terms in parentheses: -(8+3(x-4)), so:

8+3(x-4)

determiningTheFunctionDomain
3(x-4)+8

We multiply parentheses

3x-12+8

We add all the numbers together, and all the variables

3x-4

Back to the equation:

-(3x-4)



We add all the numbers together, and all the variables

-11x-(3x-4)+10=0

We get rid of parentheses

-11x-3x+4+10=0

We add all the numbers together, and all the variables

-14x+14=0

We move all terms containing x to the left, all other terms to the right

-14x=-14

x=-14/-14

x=1

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