6(2-x)=2(4+2x)

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Solution for 6(2-x)=2(4+2x) equation: 



6(2-x)=2(4+2x)

We move all terms to the left:

6(2-x)-(2(4+2x))=0

We add all the numbers together, and all the variables

6(-1x+2)-(2(2x+4))=0

We multiply parentheses

-6x-(2(2x+4))+12=0



We calculate terms in parentheses: -(2(2x+4)), so:

2(2x+4)

We multiply parentheses

4x+8

Back to the equation:

-(4x+8)



We get rid of parentheses

-6x-4x-8+12=0

We add all the numbers together, and all the variables

-10x+4=0

We move all terms containing x to the left, all other terms to the right

-10x=-4

x=-4/-10

x=2/5

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