6(2-x)=4(4x+3)

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Solution for 6(2-x)=4(4x+3) equation: 



6(2-x)=4(4x+3)

We move all terms to the left:

6(2-x)-(4(4x+3))=0

We add all the numbers together, and all the variables

6(-1x+2)-(4(4x+3))=0

We multiply parentheses

-6x-(4(4x+3))+12=0



We calculate terms in parentheses: -(4(4x+3)), so:

4(4x+3)

We multiply parentheses

16x+12

Back to the equation:

-(16x+12)



We get rid of parentheses

-6x-16x-12+12=0

We add all the numbers together, and all the variables

-22x=0

x=0/-22

x=0

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