6(2-z)=2z

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Solution for 6(2-z)=2z equation: 



6(2-z)=2z

We move all terms to the left:

6(2-z)-(2z)=0

We add all the numbers together, and all the variables

6(-1z+2)-2z=0

We add all the numbers together, and all the variables

-2z+6(-1z+2)=0

We multiply parentheses

-2z-6z+12=0

We add all the numbers together, and all the variables

-8z+12=0

We move all terms containing z to the left, all other terms to the right

-8z=-12

z=-12/-8

z=1+1/2

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