6(2/3y+1)=7y

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Solution for 6(2/3y+1)=7y equation: 



6(2/3y+1)=7y

We move all terms to the left:

6(2/3y+1)-(7y)=0



Domain of the equation: 3y+1)!=0

y∈R



We add all the numbers together, and all the variables

-7y+6(2/3y+1)=0

We multiply parentheses

-7y+12y+6=0

We add all the numbers together, and all the variables

5y+6=0

We move all terms containing y to the left, all other terms to the right

5y=-6

y=-6/5

y=-1+1/5

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