6(202y)=5(2y-2)

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Solution for 6(202y)=5(2y-2) equation: 



6(202y)=5(2y-2)

We move all terms to the left:

6(202y)-(5(2y-2))=0



We calculate terms in parentheses: -(5(2y-2)), so:

5(2y-2)

We multiply parentheses

10y-10

Back to the equation:

-(10y-10)



We get rid of parentheses

6202y-10y+10=0

We add all the numbers together, and all the variables

6192y+10=0

We move all terms containing y to the left, all other terms to the right

6192y=-10

y=-10/6192

y=-5/3096

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