6(2b+3)=-3b+4(5b+7)

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Solution for 6(2b+3)=-3b+4(5b+7) equation: 



6(2b+3)=-3b+4(5b+7)

We move all terms to the left:

6(2b+3)-(-3b+4(5b+7))=0

We multiply parentheses

12b-(-3b+4(5b+7))+18=0



We calculate terms in parentheses: -(-3b+4(5b+7)), so:

-3b+4(5b+7)

We multiply parentheses

-3b+20b+28

We add all the numbers together, and all the variables

17b+28

Back to the equation:

-(17b+28)



We get rid of parentheses

12b-17b-28+18=0

We add all the numbers together, and all the variables

-5b-10=0

We move all terms containing b to the left, all other terms to the right

-5b=10

b=10/-5

b=-2

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