6(2b-2)=7b+28

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Solution for 6(2b-2)=7b+28 equation:



6(2b-2)=7b+28
We move all terms to the left:
6(2b-2)-(7b+28)=0
We multiply parentheses
12b-(7b+28)-12=0
We get rid of parentheses
12b-7b-28-12=0
We add all the numbers together, and all the variables
5b-40=0
We move all terms containing b to the left, all other terms to the right
5b=40
b=40/5
b=8

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