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6(2b-3)=-2(5b+9)
We move all terms to the left:
6(2b-3)-(-2(5b+9))=0
We multiply parentheses
12b-(-2(5b+9))-18=0
We calculate terms in parentheses: -(-2(5b+9)), so:We get rid of parentheses
-2(5b+9)
We multiply parentheses
-10b-18
Back to the equation:
-(-10b-18)
12b+10b+18-18=0
We add all the numbers together, and all the variables
22b=0
b=0/22
b=0
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