6(2b-4)b=4

Solution for 6(2b-4)b=4 equation:

6(2b-4)b=4

We move all terms to the left:

6(2b-4)b-(4)=0

We multiply parentheses

12b^2-24b-4=0

a = 12; b = -24; c = -4;
Δ = b2-4ac
Δ = -242-4·12·(-4)
Δ = 768
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{768}=\sqrt{256*3}=\sqrt{256}*\sqrt{3}=16\sqrt{3}$
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-24)-16\sqrt{3}}{2*12}=\frac{24-16\sqrt{3}}{24}
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-24)+16\sqrt{3}}{2*12}=\frac{24+16\sqrt{3}}{24}
$