6(2b-5)+3=10

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Solution for 6(2b-5)+3=10 equation: 



6(2b-5)+3=10

We move all terms to the left:

6(2b-5)+3-(10)=0

We add all the numbers together, and all the variables

6(2b-5)-7=0

We multiply parentheses

12b-30-7=0

We add all the numbers together, and all the variables

12b-37=0

We move all terms containing b to the left, all other terms to the right

12b=37

b=37/12

b=3+1/12

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