6(2c+1)=3c-2(c+10)

Solution for 6(2c+1)=3c-2(c+10) equation:

Simplifying
6(2c + 1) = 3c + -2(c + 10)

Reorder the terms:
6(1 + 2c) = 3c + -2(c + 10)
(1 * 6 + 2c * 6) = 3c + -2(c + 10)
(6 + 12c) = 3c + -2(c + 10)

Reorder the terms:
6 + 12c = 3c + -2(10 + c)
6 + 12c = 3c + (10 * -2 + c * -2)
6 + 12c = 3c + (-20 + -2c)

Reorder the terms:
6 + 12c = -20 + 3c + -2c

Combine like terms: 3c + -2c = 1c
6 + 12c = -20 + 1c

Solving
6 + 12c = -20 + 1c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-1c' to each side of the equation.
6 + 12c + -1c = -20 + 1c + -1c

Combine like terms: 12c + -1c = 11c
6 + 11c = -20 + 1c + -1c

Combine like terms: 1c + -1c = 0
6 + 11c = -20 + 0
6 + 11c = -20

Add '-6' to each side of the equation.
6 + -6 + 11c = -20 + -6

Combine like terms: 6 + -6 = 0
0 + 11c = -20 + -6
11c = -20 + -6

Combine like terms: -20 + -6 = -26
11c = -26

Divide each side by '11'.
c = -2.363636364

Simplifying
c = -2.363636364