6(2c+4)+12=12c+36

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Solution for 6(2c+4)+12=12c+36 equation:



6(2c+4)+12=12c+36
We move all terms to the left:
6(2c+4)+12-(12c+36)=0
We multiply parentheses
12c-(12c+36)+24+12=0
We get rid of parentheses
12c-12c-36+24+12=0
We add all the numbers together, and all the variables
=0
c=0/1
c=0

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