6(2c-3)+8c=9

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Solution for 6(2c-3)+8c=9 equation: 



6(2c-3)+8c=9

We move all terms to the left:

6(2c-3)+8c-(9)=0

We add all the numbers together, and all the variables

8c+6(2c-3)-9=0

We multiply parentheses

8c+12c-18-9=0

We add all the numbers together, and all the variables

20c-27=0

We move all terms containing c to the left, all other terms to the right

20c=27

c=27/20

c=1+7/20

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