6(2c-7)+16=2(4c-1)+8

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Solution for 6(2c-7)+16=2(4c-1)+8 equation:


Simplifying
6(2c + -7) + 16 = 2(4c + -1) + 8

Reorder the terms:
6(-7 + 2c) + 16 = 2(4c + -1) + 8
(-7 * 6 + 2c * 6) + 16 = 2(4c + -1) + 8
(-42 + 12c) + 16 = 2(4c + -1) + 8

Reorder the terms:
-42 + 16 + 12c = 2(4c + -1) + 8

Combine like terms: -42 + 16 = -26
-26 + 12c = 2(4c + -1) + 8

Reorder the terms:
-26 + 12c = 2(-1 + 4c) + 8
-26 + 12c = (-1 * 2 + 4c * 2) + 8
-26 + 12c = (-2 + 8c) + 8

Reorder the terms:
-26 + 12c = -2 + 8 + 8c

Combine like terms: -2 + 8 = 6
-26 + 12c = 6 + 8c

Solving
-26 + 12c = 6 + 8c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-8c' to each side of the equation.
-26 + 12c + -8c = 6 + 8c + -8c

Combine like terms: 12c + -8c = 4c
-26 + 4c = 6 + 8c + -8c

Combine like terms: 8c + -8c = 0
-26 + 4c = 6 + 0
-26 + 4c = 6

Add '26' to each side of the equation.
-26 + 26 + 4c = 6 + 26

Combine like terms: -26 + 26 = 0
0 + 4c = 6 + 26
4c = 6 + 26

Combine like terms: 6 + 26 = 32
4c = 32

Divide each side by '4'.
c = 8

Simplifying
c = 8

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