6(2c-8)+3=15

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Solution for 6(2c-8)+3=15 equation: 



6(2c-8)+3=15

We move all terms to the left:

6(2c-8)+3-(15)=0

We add all the numbers together, and all the variables

6(2c-8)-12=0

We multiply parentheses

12c-48-12=0

We add all the numbers together, and all the variables

12c-60=0

We move all terms containing c to the left, all other terms to the right

12c=60

c=60/12

c=5

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